A 16 L sample of gas is under a pressure of 4.6 atm. What will be the pressure of the gas when the volume increases to 20 L? Assume the temperature is held constant.

P₂ = 3.68 atm

Explanation:

Given data:

Initial volume of sample = 16 L

Initial pressure = 4.6 atm

Final pressure = ?

Final volume = 20 L

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

4.6 atm × 16 L = P₂ × 20 L

P₂ = 73.6 atm. L/ 20 L

P₂ = 3.68 atm

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )