At what temperature will 5.00 g of F2, exert a pressure of 119.96 kPa at a volume of 750.0 mL?

-183.15 °C

Explanation:

Given data:

Mass of F₂ = 5.00 g

Pressure = 119.96 KPa (119.96/101 = 1.2 atm)

Volume = 750.0 mL ( 750.0/1000 = 0.75L)

Temperature = ?

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/molar mass

Number of moles = 5.00 g/ 38g/mol

Number of moles = 0.13 mol

Now we will calculate the temperature:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1.2 atm × 0.75 L = 0.13 mol ×0.0821 atm.L/ mol.K  × T

0.9 atm.L = 0.01 atm.L/ K  × T

T = 0.9 atm.L /0.01 atm.L/ K

T = 90 K

Kelvin to degree celsius:

90K -273.15 = -183.15 °C

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.

no, the red giant is the hottest with 2.00.000.000 degrees celsius. while the white dwarf only 25,000 degrees celsius.