What is the ionic equation for:
cuso4(aq) + bacl2(aq) cucl2(aq) + baso4(s)

                        CuSO₄(aq) + BaCl₂(aq) → CuCl₂(aq) + BaSO₄(s)
Cu⁺(aq) + SO₄⁻(aq) + Ba⁺(aq) + Cl₂⁻(aq) → Cu⁺(aq) + Cl₂⁻(aq) + BaSO₄(s)
                                SO₄⁻(aq) + Ba⁺(aq) → BaSO₄(s)

Ibelieve the answer 4 moles

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.