Determine the missing value of ΔS⁰298 (in J/K/mol). N(g) + O(g) → NO(g)
ΔS⁰298 = ?
N2(g) + O2(g) → 2 NO(g)
ΔS⁰298 = 24.8 J/K/mol
N2(g) → 2 N(g)
ΔS⁰298 = 115.0 J/K/mol
O2(g) → 2 O(g)
ΔS⁰298 = 117.0 J/K/mol

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

i believe it is a.) released into

explanation:

it's c (engineer's do their work with mechanical stuff not on any living being)