Alexandra is preforming this combustion reaction i lab: C3H8 + 5O2 + 3CO + 4h20. If she carefully measures out 220 g of C3H8 and discovers she has produced 660 g of carbon dioxide and 360 g of water, how many grams of oxygen must have been required to react with the C3H8?

800 g of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Next, we shall determine the masses of C3H8 and O2 that reacted from the balanced equation. This is illustrated below:

Molar mass of C3H8 = (12×3) + (8×1)

= 36 + 8

= 44 g/mol

Mass of C3H8 from the balanced equation = 1 × 44 = 44 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 5 × 32 = 160 g

From the balanced equation above,

44 g of C3H8 reacted with 160 g of O2.

Finally, we shall determine the mass of O2 needed to react with 220 g of C3H8. This can be obtained as follow:

From the balanced equation above,

44 g of C3H8 reacted with 160 g of O2.

Therefore, 220 g of C3H8 will react with = (220 × 160)/44 = 800 g of O2.

Thus, 800 g of O2 is needed for the reaction.