(NH4)3PO4 + CaBr2 = Ca3(PO4)2 + NH4Br
ionic equation

2(NH4)3PO4 + 3CaBr2 → Ca3(PO4)2 + 6NH4Br

Explanation:

Tribasic Ammonium Phosphate + Calcium Bromide = Tricalcium Phosphate + Ammonium Bromide

Reaction Type

Double Displacement (Metathesis)

Reactants

Tribasic Ammonium Phosphate - (NH4)3PO4

Ammonium Phosphate

Molar Mass of H12N3O4P Oxidation State of H12N3O4P

Calcium Bromide - CaBr2

Kalziumbromid CaBr2 Calcium Bromide Hydrate

Molar Mass of Br2Ca Oxidation State of Br2Ca

Products

Tricalcium Phosphate - Ca3(PO4)2

Bone Phosphate Of Lime BCP TCP Tricalcium Orthophosphate Calcium Phosphate Tertiary Calcium Phosphate Calcium Orthophosphate Ca3(PO4)2

Molar Mass of Ca3O8P2 Oxidation State of Ca3O8P2

Ammonium Bromide - NH4Br

NH4Br

Molar Mass of BrH4N Oxidation State of BrH4N

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explanation:

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answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.