What volume of 0.100M Na3PO4 is required to precipitate all the lead(II) ions from 100.0 mL of 0.400M Pb(NO3)2

Explanation:

M1V1=M2V2

M1=0.100M

M2=0.400M

V2=100.0*10^-3

V1=?

M1V1=M2V2

V1=M2V2/M1

V1=0.400*0.100/100.0*10^-3

V1=0.4

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