How many grams of NO2 would be formed from 1.0 mole of NO and excess of O2?

Mass = 46 g

Explanation:

Given data:

Number of moles of NO = 1.0 mol

Amount of O₂ = excess

Mass of NO₂ formed = ?

Solution:

Chemical equation:

2NO + O₂    →    2NO₂

Now we will compare the moles of No with NO₂.

                  NO           :           NO₂

                    2            :            2

                     1            :           1

Mass of NO₂ in gram:

Mass = number of moles × molar mass

Mass = 1 mol ×46 g/mol

Mass = 46 g

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )