If a 5.00% citric acid solution contains 5.00 grams of citric acid in every 100.0 mL of the solution, how many grams of citric acid are present in 375 mL of the 5.00% (w/v) solution? show your work using dimensional analysis and report your answer with the correct number of significant figures

18.8 g Citric acid

Explanation:

We have a 5.00% (w/v) citric acid solution, that is, there are 5.00 grams of citric acid every 100.0 mL of the solution. We can use dimensional analysis to calculate the grams of citric acid in 375 mL of the 5.00% (w/v) solution.

375 mL Solution × (5.00 g Citric acid/100.0 mL Solution) = 18.8 g Citric acid

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).