What is the energy of a photon of red light having a frequency of 3.08 x 10^14 HZ?

2.04 x 10⁻¹⁹J

Explanation:

Given parameters:

  Frequency = 3.08 x 10¹⁴Hz

Unknown:

The energy of the photon  = ?

Solution:

 The energy of a photon is given as;

          E = hf

Where h is the planck's constant

            f is the frequency

Insert the parameters and solve;

           E = 6.63 x 10⁻³⁴ x 3.08 x 10¹⁴

          E = 20.4 x 10⁻³⁴⁺¹⁴

           E = 20.4 x 10⁻²⁰  = 2.04 x 10⁻¹⁹J

answer: you could do some invislibe ink.

explanation: i will tell you how to if u answer my question.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.