The half-life of carbon-14 is 5,730 years. If you started with 100.0 g of carbon-14, how

much would remain after 4 half-lives?

The correct answer is 6.25g.

Explanation:

The half-life of a radioactive isotope is given by the formula where a  is the initial amount of the substance, b  is the decay factor, and x  is the time elapsed (this is also known as the exponential decay function). We can define our values and substitute them into the equation.

Now, if we place this into the equation, we can solve for the amount of carbon-14 that will remain after it radioactively decays four times.

Because you are given 3 significant figures in the problem (100.0), we don't need to round 6.25g up or down.

Note: Remember to apply your BPEMDAS ruling when simplifying the equation. Therefore, you should simplify your work in the parentheses first. Then, evaluate the solved value and raise it to the power of the exponent. Finally, you can distribute your initial value and solve for y.

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.

cytokinesis is the splitting of a cell membrane to form 2 identical daughter cells. it's similar to mitosis as both cells have identical copies of dna and cytokinesis is a step in the mitotic cycle.