6 16.34) Show that 5000 cal are required to increase the temperature of 50 g of water from 0°C to 100°C. The specific heat capacity for
water is 1 cal/g °C

Detail is given below.

Explanation:

Given data:

Mass of water = 50 g

Initial temperature = 0°C

Final temperature = 100°C

Specific heat capacity of water = 1 cal/g.°C

Calories absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 100°C - 0°C =  100°C

Now we will put the values in formula.

Q = 50 g×1 cal/g.°C ×100°C

Q = 5000 cal

Hence, it is proved that 5000 calories required to increase the temperature of 50 g of water from 0°C to 100°C.

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph