An unknown sample is being evaluated in lab. What is the specific heat capacity of the compound if it requires 170.97raise the temperature of 54.07 grams of the unknown from 15.2 degrees * C to 33.5 °C.

Specific heat capacity =  0.173 j/g.°C

Explanation:

Given data:

Mass of sample = 54.07 g

Heat required = 170.97 j

Initial temperature = 15.2 °C

Final temperature = 33.5°C

Specific heat capacity = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 33.5°C - 15.2°C

ΔT = 18.3°C

170.97 j = 54.07 g × c ×  18.3°C

170.97 j = 989.48 g.°C  × c

c = 170.97 j /989.48 g.°C

c = 0.173 j/g.°C

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

c.

explanation: