A 1.25g sample of copper (cCu=0.386Jg∘C) is initially at a temperature of 25.0∘C. If the sample absorbs 87.4J of heat, what is its final temperature? Report your answer with the correct number of significant figures.

Final temperature = 206∘C

Explanation:

Heat Energy is given as  

q= mCΔT

ehere

q= Heat energy = 87.4J

m= mass=1.25g

C=specific heat c= 0.386Jg∘C) ,

ΔT =  Change in temperate of which the final temperature= 25.0∘C

 q= mCΔT

ΔT = q/mC

ΔT = 87.4/ 1.25 X 0.386=181.14∘C

But,

T final- T initial = ΔT

T final = T initial + ΔT

T final = 25.0∘C +181.14∘C=206.14∘C rounded to 206∘C

the answer is 0.42 is that is an option. this question provides no info