Match the options to correct boxes to write the formula for Iron(II) chloride: FeCl2
I need help!!

The correct order are;

1) Multivalent metal cation

2) Charge on multivalent metal cation

3) Non metal anion

4) Charge on anion

5) Number of ions needed to neutralize +ve cation

6) Final Formula

7) FeCl₂

Please find attached the required solution diagram

Explanation:

Iron, Fe, which is a transition metal, form compounds in which it exists as +3 and +2, therefore, it is a multivalent metal

The amount (number) of charge from the anion with a charge of -1, needed to neutralize the +2 charge in the multivalent metal cation is 2

The final compound formed between the anion and the cation is therefore FeCl₂

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the correct answer would be d. hope this !