A 25.0 mL sample of a saturated C a ( O H ) 2 solution is titrated with 0.023 M H C l , and the endpoint is reached after 38.0 mL of titrant are dispensed. Based on this data, what is the concentration (M) of C a ( O H ) 2

The concentration of solution is 0.01748M .

Explanation:

Let us calculate -

Firstly , lets calculate

Given - Volume of sample of = 25.0ml

             Volume of sample of HCL solution = 38.0ml

             Concentration of HCL solution = 0.023M

            Concentration of Ca(OH) solution = ?

Now,

Putting the given values-

Thus, the concentration of ions is 0.03496M

For, concentration of

                                                 = 0.5 x 0.03496M

                                            = 0.01748M

Thus , concentration of solution is 0.01748M.

Hence , the answer is 0.01748M

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