If 342.2 grams of C12H22O11 (sucrose) is dissolved in 1.0 L of solution. What is the molar concentration of the solution? Report your answer with the correct number of significant figures.

M = 1 M

Explanation:

Given data:

Mass in gram = 342.2 g

Volume of solution = 1.0 L

Molar concentration = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of sucrose:

Number of moles = mass/molar mass

Number of moles = 342.2 g/ 342.2 g/mol

Number of moles = 1 mol

Molarity:

M = 1 mol / 1.0 L

M = 1 mol/L

M = 1 M

the answer is 75.0%.

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