Plz help me with this: Write the complete electron configuration, short hand electron configuration, and the orbital diagram. For the orbital diagram, use "u" for "upward arrow" and "d" for "downward arrow".
1) H
2) Ni
3) N
4) I and I^-1
5) Ca and Ca^+2
6) C
7) O and O^-2
8) Co
9) Ag and Ag^+1
10) Ar

We are to write the orbital notation and electronic configuration of sulfur and iron.

The orbital notation shows the filling of electrons into orbitals or sublevels.

Electron configuration  shows the distribution of electrons into shells;

       Number of electrons     Electron configuration     Orbital notation

S                  16                                   2 8 6                      1s² 2s² 2p⁶ 3s² 3p⁴

Fe                26                                2, 8, 14 2           1s² 2s² 2p⁶ 3s² 3p⁶3d⁶4s²        

Explanation:

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

the answer is c. nacl