1. Calculate the enthalpy change for the reaction C2H4 (g) + H2(g) - C2H6 (g) delta H = ?
given the following delta H values. Water formed in all reactions is in the liquid phase:
a. delta H = -1410.9 kJ mol•C2H4 (g) for the combustion of C2H4 (g)

b. delta H = -1559.7 kJ mol1 C2H6 (g) for the combustion of CzH6 (g)

C. delta H+ = -285.3 kJ mol-1 H2O for the formation of water (1)

Combustion is the act or process of burning. therefore, i believe the answer is  a: burning wood. 

B. nuclear reactions could first occur.

First up write the aim
then write the materials reqd.
then the procedure which you follow
then observation
then conclusion
then you can write lab safety rules or precautions(you can avoid if u want).
lemme' give an example
aim: to observe the double displacement reaction
materials reqd: bacl2 and na2so4, test tubes and a dropper
procedure:
1. take bacl2 in a test tube and na2so4 in the other.
2. then pour bacl2 into na2so4 solution.
3. observe
observation:
you will see that a white precipitate is formed called baso4. along with that common salt or nacl is formed.
the equation is
bacl2+na2so4=baso4+2nacl
conclusion:
a double displacement reaction is observed.
hope it