If KI K I has a solubility of 140. G g in 100. G g of H2O H 2 O at 20 ∘C ∘ C , how many grams of water are needed to prepare a saturated solution containing 75.0 g g of KI K I ?

53.6g of water are needed

Explanation:

Solubility is the maximum amount that a solvent can dissolve of a particular solute.

100g of Water can dissolve 140g of KI.

That is also the definition of a satured solution: A solution that is dissolved in the maximum amount in a particular amount of solvent.

If there are dissolved 75.0g of KI, the amount of water needed are:

75g KI * (100g water / 140g KI) =

answer; economic order quantity;

explanation:

i think option no d is the correct answer