For the reaction 2H2S(g) – 2H2(g) + S2(g), Kc = 9.1x102 at 750 K. What will happen when 0.10 mol of H2S, 1.0 mol of H2, and 1.5 mol of S2 are added
to a 1.0-L container and the system is brought to 750 K?
Nothing; the system is at equilibrium.
More H2S will be formed.
More S2 will be formed than H2.
The amount of H2 formed will be half the amount of S2 formed.
More H2 will be formed than S2.

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