a solution of silver (i) nitrate and a solution of calcium bromate react and produce a splice precipitate of silver bromate

2 AgNO₃(aq) + Ca(BrO₃)₂(aq) ⇒ Ca(NO₃)₂(aq) + 2 AgBrO₃(s)

2 Ag⁺(aq) + 2 NO₃⁻(aq) + Ca²⁺(aq) + 2 BrO₃⁻(aq) ⇒ Ca²⁺(aq) + 2 NO₃⁻(aq) + 2 AgBrO₃(s)

2 Ag⁺(aq) + 2 BrO₃⁻(aq) ⇒ 2 AgBrO₃(s)

Explanation:

The question is missing but I think it must be about the chemical equations.

Let's consider the molecular equation that occurs when a solution of silver nitrate and a solution of calcium bromate react.

2 AgNO₃(aq) + Ca(BrO₃)₂(aq) ⇒ Ca(NO₃)₂(aq) + 2 AgBrO₃(s)

The complete ionic equation includes all the ions and the insoluble species.

2 Ag⁺(aq) + 2 NO₃⁻(aq) + Ca²⁺(aq) + 2 BrO₃⁻(aq) ⇒ Ca²⁺(aq) + 2 NO₃⁻(aq) + 2 AgBrO₃(s)

The net ionic equation includes only the ions that participate in the reaction and the insoluble species.

2 Ag⁺(aq) + 2 BrO₃⁻(aq) ⇒ 2 AgBrO₃(s)

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

i think so it’s will be b yes i believe its