How many nitrogen atoms are present in 25.00 g in N2O5?

2.79 x 10²³atoms

Explanation:

Given parameters:

Mass of N₂O₅  = 25g

Unknown:

Number of atoms of Nitrogen present  = ?

Solution:

To solve this problem, it is best to find the number of moles of nitrogen present in the sample first.

 Number of moles =

  Molar mass of N₂O₅  = 2(14) + 5(16) = 108g/mol

  Number of moles  =   = 0.23mol

  1 mole of N₂O₅ contains 2 mole of N

  0.23 mole of  N₂O₅ will contain 0.23 x 2  = 0.46mole of N

  1 mole of a substance  = 6.02 x 10²³ atoms

  0.46 mole of nitrogen  = 0.46 x 6.02 x 10²³ atoms = 2.79 x 10²³atoms

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