How many violet photons 7.5 X 10^14 Hz would are necessary to provide the energy of a single AA battery that contains 1300 J? answer numerically using scientific notation with e and significant figures.

2.6 * 10^21 photons

Explanation:

First we obtain the energy of one photon.

The energy of one photon = hf

h= Planks constant = 6.6 * 10^-34 Js

f = frequency of the radiation =  7.5 X 10^14 Hz

E = 6.6 * 10^-34 *  7.5 X 10^14

E= 49.5 * 10^-20 J

Number of photons = Total energy/ energy of one photon

Total energy = 1300 J

Number of photons = 1300/49.5 * 10^-20

Number of photons = 2.6 * 10^21 photons

the answer is d : ) have a good da

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