A gas has a volume of 6.00 liters at a temperature of 27° C and a pressure of 1,00 atm. What is the volume of the gas, in liters, at a temperature of 327°C and a pressure of 3.00 atm?

We are given:

P1 = 1 atm                 P2 = 3 atm

T1 = 300 K               T2 = 600 K

V1 = 6 L                    V2 = v L

Finding the final Volume:

From the ideal gas equation:

PV = nRT

since in the given scenario, the universal gas constant (R) and number of moles(n) are constant

So, for both the cases, the value of n*R will be a constant k

Hence, we can write that:

PV / T = k        [where k is a constant]

Since the constant 'k' is the same for both the cases, we can write that:

P1V1 / T1 = P2V2 / T2

replacing the variables

1 * 6 / 300 = 3 * v / 600

1/50 = v / 200

v = 200/50

v = 4 L

Therefore, the volume of the gas at 600K and 3 atm will have a volume of 4 L

answer; (d) constructive and destructive force;

linda: 3 ; laura: 15

step-by-step explanation:

note that linda + laura's age is 18, and that linda is 12 years younger than her sister.

let "linda" = x , "laura" = y:

x + y = 18

x = y - 12

first, plug in y - 12 for x in the first equation:

(y - 12) + y = 18

simplify.

2y - 12 = 18

isolate the variable (y). note the equal sign, what you do to one side, you do to the other. do the opposite of pemdas. first add, then divide.

2y - 12 (+12) = 18 (+12)

2y = 18 + 12

2y = 30

(2y)/2 = (30)/2

y = 30/2

y = 15

next, plug in 15 for y in the second equation (the other equation would work too).

x = y - 12

x = (15) - 12

x = 3

linda's age is 3, laura's age is 15.

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