What is the frequency of a photon whose energy is 3.4 x 10-19 J?

5.13×¹⁴ Hz

Explanation:

The following data were obtained from the question:

Energy (E) = 3.4×10¯¹⁹J

Frequency (f) =?

Energy and frequency are related by the following formula:

E = hf

Where:

E is the energy.

h is the Planck's constant.

f is the frequency.

Thus, we can obtain the frequency of the photon by using the above formula as illustrated below:

Energy (E) = 3.4×10¯¹⁹J

Planck's constant (h) = 6.63×10¯³⁴ Js

Frequency (f) =?

E = hf

3.4×10¯¹⁹ = 6.63×10¯³⁴ × f

Divide both side by 6.63×10¯³⁴

f = 3.4×10¯¹⁹ / 6.63×10¯³⁴

F = 5.13×¹⁴ Hz

Thus, the frequency of the photon is 5.13×¹⁴ Hz.

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).