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Chemistry, 13.11.2020 16:40 cynayapartlow88

If 1.65 g of Cu(NO_3)_2 are obtained from allowing 0.93 g of Cu to react with excess HNO3, what is the percent yield of the reaction? (Mw of Cu(NO_3)_2 = 187.56 g/mol, Mw of Cu = 63, 546 g/mol)Cu (s) + 2HNO_3 (aq) --> Cu(NO_3)_2 (aq) + H_2(g)(a) 60%(b) 70%(c) 93%

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