Chemistry, 25.01.2020 07:31 sansyboy7891

What is the mass percent of aluminum in al(oh)3 the molar mass of al = 26.98, h = 1.0079, and o = 16.00

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Answer from: luis759

34.58%

Explanation:-

Mass percentage is the ratio of mass of a particular element present in the total mass of the substance in terms of percentage.

$Mass\ %=\frac{\text{Mass of} Al}{\text{Mass of} Al(OH)_3}\times 100\ %$

Given: mass of AL = 26.98, H = 1.0079, and O = 16.00

Thus mass of $Al(OH)_3=26.98+3\times 16+3\times 1.0079=78.0037g$

Putting the values in the equation:

$Mass\%=\frac{26.98g}{78.0037g/mol}\times 100\ %=34.58\ %$

Thus mass percent of aluminum in Al(OH)_3 is 34.58%.

Answer from: Quest

definition

entropy is a measure of the randomness or the extent of disorder of a chemical process.

enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

entropy is measured in joule per kelvin (jk⁻¹) whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

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What is the mass percent of aluminum in al(oh)3 the molar mass of al = 26.98, h = 1.0079, and o = 16...

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