I need to answer the following question with the given chemical equation. K2CO3 (aq) + CaCl2 (aq) → CaCO3 (s) + 2 KCl (aq)

Calculate the mass of KCl produced if 12.6 mL of 0.0587 M CaCl2 reacts with excess K2CO3.

If you could show me the steps to do it as well that would be even better!

Most smaller stars don't have a radiative zone.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na

It can be classified based on its