What volume is occupied by5.3 mol of c02 at 28c and a pressure of .998 atm

V  = 131.23 L

Explanation:

Given data:

Moles of CO₂ = 5.3 mol

Temperature = 28°C

Pressure = 0.998 atm

Volume occupied = ?

Solution:

Formula:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

28+273 = 301 K

0.998 atm ×V = 5.3 mol × 0.0821 atm.L/ mol.K  × 301 K

V = 130.97 atm.L / 0.998 atm

V  = 131.23 L