If I dilute 250 mL of 0.10 M lithium acetate solution to a volume of 750 mL, what will the concentration of this solution be?

0.033 M

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V1) = 250 mL

Molarity of stock solution (M1 ) = 0.10 M

Volume of diluted solution (V2) = 750 mL

Molarity of diluted solution (M2) =.?

Thus, we can obtain the molarity of the diluted solution by using the dilution formula as illustrated below:

M1V1 = M2V2

0.1 × 250 = M2 × 750

25 = M2 × 750

Divide both side by 750

M2 = 25/750

M2 = 0.033 M

Therefore, the molarity of the diluted solution is 0.033 M.

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