If 4.89 g of ZnCl2 is dissolved in enough water to give a total volume of 500 mL, what is the molarity of the solution

The molarity of the solution if 4.89 g of ZnCl2 is dissolved in enough water to give a total volume of 500 mL is 0.072M.

HOW TO CALCULATE MOLARITY:

= 136g/mol

Therefore, the molarity of the solution if 4.89 g of ZnCl2 is dissolved in enough water to give a total volume of 500 mL is 0.072M.

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Molarity = 0.08 M

Explanation:

Given data:

Mass of ZnCl₂ = 4.89 g

Volume of water = 500 mL (500 mL× 1L/1000 mL= 0.5 L)

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of mole ZnCl₂:

Number of moles = mass/molar mass

Number of moles = 4.89 g/ 136.3 g/mol

Number of moles = 0.04 mol

Molarity:

M = 0.04 mol / 0.5 L

M = 0.08 M