Tia learns that the temperature of rock in Earth's mantle varies depending on its location. Rock located close to the lithosphere is about 1,000 °C, and rock located close to the outer core is about 3,700 °C.
Tia uses the formula shown below to calculate the amount of heat that needs to be added to a 5-9 piece of rock
in order to raise its temperature from 1,000 °C to 3,700 °C. She uses 0.79 J/g °C for the specific heat of the rock.
q=MCAT
q= amount of heat
m= mass
C = specific heat
AT=change in temperature
What is the amount of heat, in joules, that needs to be added to the piece of rock.
OA
2,706 joules
B
3,950 joules
С
10,665 joules
D
14,615 joules

At 40 âc the solution has at 40 â c the solution has blank g of k n o 3 per 100 g of water and it can contain up to blank g of k n o 3 per 100 g of water. at 0 â c the solubility is ~ blank g k n o 3 per 100 g of water, so ~ blank g k n o 3 per 100 g of water will precipitate out of solution.g of kno3 per 100 g of water and it can contain up to at 40 â c the solution has blank g of k n o 3 per 100 g of water and it can contain up to blank g of k n o 3 per 100 g of water. at 0 â c the solubility is ~ blank g k n o 3 per 100 g of water, so ~ blank g k n o 3 per 100 g of water will precipitate out of solution.g of kno3 per 100 g of water. at 0 âc the solubility is ~ at 40 â c the solution has blank g of k n o 3 per 100 g of water and it can contain up to blank g of k n o 3 per 100 g of water. at 0 â c the solubility is ~ blank g k n o 3 per 100 g of water, so ~ blank g k n o 3 per 100 g of water will precipitate out of solution.kno3 per 100 g of water, so ~ at 40 â c the solution has blank g of k n o 3 per 100 g of water and it can contain up to blank g of k n o 3 per 100 g of water. at 0 â c the solubility is ~ blank g k n o 3 per 100 g of water, so ~ blank g k n o 3 per 100 g of water will precipitate out of solution.gkno3 per 100 g of water will precipitate out of solution. a kno3 solution containing 55 g of kno3 per 100.0 g of water is cooled from 40 ∘c to 0 ∘c. what will happen during cooling?

0.2348 grams of pbcl2 used to form 44.0 ml of solution.

Given that 1 mi = 1760 yd, determine what conver- sion factor is appropriate to convert 1849 yd to miles; to convert 2.781 mi to yards.