Find the Molarity of 6.25 grams of barium nitrate dissolved in 250 mL solution.

0.0956 M

Explanation:

Step 1: Calculate the moles corresponding to 6.25 g of barium nitrate (solute)

The molar mass of barium nitrate is 261.34 g/mol.

6.25 g × 1 mol/261.34 g = 0.0239 mol

Step 2: Convert the volume of solution to liters

We will use the conversion factor 1 L = 1000 mL.

250 mL × 1 L/1000 mL = 0.250 L

Step 3: Calculate the molarity of the solution

The molarity is equal to the moles of solute divided by the liters of solution.

M = 0.0239 mol / 0.250 L = 0.0956 M

the answer for sodium is 0.186

the answer for rubidium is 0.251