Chemistry, 17.11.2020 04:40 chelsilconway2262
The decomposition of calcium carbonate, CaCO3(s) > CaO(s)+CO2(g), has the following values for free energy and enthalpy at 25.0°C
/\G=130.5 kJ/mol
/\H=178.3 kJ/mol
What is the entropy of the reaction?
Use /\G=/\H-T/\S
A. -160.3J/(mol. K)
B. -47.8J/(mol. k)
C. 160.3 J/(mol. k
D. 1912 j/(mol. k
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