If the pressure exerted by a gas at 25 degrees C in a volume of 0.044 L is 3.81 atm, how many moles of gas are present?

The moles of gas has a pressure of 3.81 atm and volume 0.044 L has been 6.85 mmol.

The gas has been exhibiting the ideal nature. According to the ideal gas equation:

PV =nRT

P = pressure = 3.81 atm

V = volume = 0.044 L

R = constant = 0.0821

T = temperature = 25 = 298 K

Substituting the value:

3.81 0.044 = n  0.0821  298

0.16764 = 24.4658 n

n = 0.00685 mol

n = 6.85 mmol

The moles of gas has a pressure of 3.81 atm and volume 0.044 L has been 6.85 mmol.

For more information about the pressure of a gas, refer to the link:

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0.0069 mol

Explanation:

Given data:

Temperature = 25°C

Volume of gas = 0.044 L

Pressure of gas = 3.81 atm

Number of moles of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

25+273 = 298 K

3.81 atm × 0.044 L = n × 0.0821 atm.L/ mol.K  ×  298 K

0.17  atm.L = n ×24.47 atm.L/ mol

n = 0.17  atm.L/24.47 atm.L/ mol

n = 0.0069 mol

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.

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