355 g of chlorine gas (MW = 70.9 g/mol) isheld in a vessel with a fixed volume of 70.0 L. What is the pressure of the gas in atmospheres if it's temperature is 30.0 degrees celcius?

1.78 atm

Explanation:

From the question given above, the following data were obtained:

Mass of Cl = 355 g

Molecular weight of Cl = 70.9 g/mol

Volume (V) = 70.0 L

Temperature (T) = 30 °C

Pressure (P) =?

Next, we shall determine the number of mole in 355 g of chlorine (Cl). This can be obtained as follow:

Mass of Cl = 355 g

Molecular weight of Cl = 70.9 g/mol

Mole of Cl =.?

Mole = mass /molecular weight

Mole of Cl = 355 /70.9

Mole of Cl = 5 moles

Next, we shall convert 30 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 30 °C

Temperature (T) = 30 °C + 273 = 303 K

Finally, we shall determine the pressure of the gas as illustrated below:

Volume (V) = 70.0 L

Number of mole (n) = 5 moles

Temperature (T) = 303 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 70 = 5 × 0.0821 × 303

P × 70 = 124.3815

Divide both side by 70

P = 124.3815 / 70

P = 1.78 atm

Therefore, the pressure of the gas is 1.78 atm

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023 

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.