How many Joules of heat are needed to raise the temperature from 50°C
to 95°C for 35 g of water?

Q = 6583.5 J

Explanation:

Given data:

Heat required = ?

Mass of water = 35 g

Initial temperature = 50°C

Final temperature = 95°C

Solution:

Specific heat capacity of water is 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = 95°C - 50°C

ΔT  = 45°C

Q = 35 g×4.18 j/g.°C × 45°C

Q = 6583.5 J

i just learnt this recently but i need to look through my notes again