If 90 grams of gold has a volume of 5 cm 3 , calculate the density (include the units and show your work or you get no credit) AND

If the density of a diamond is 3.5 g/cm 3 , what would be the mass of a diamond whose volume is 0.5 cm 3(include the units and show your work or you get no credit).

Answer earth,water,fire and air;

The higher the temperature, the increased rate constant for a reaction.(positive linear association)

Aquantity of that isotope to decay to 1/2 of  its original value

Use the universal gas law formula: pv = nrt now, the key word in this problem is stp, so at stp, temperature will always be 0 degrees celsius and pressure will always be 1.0 atm or 760 torr. given something is at stp, we already know the two variables pressure and temperature. the other thing we can find with the given information is moles. to find moles, just divide grams by molar mass of the element. 16.0g / 2(16.00)g/mol = 0.5 moles plug the values in to the equation pv = nrt (1.0 atm)( x ) = (0.5 )(0+273=273k) the r value is just a constant for when we use atm, liters, moles and kelvin. i'm assuming you want your answer in liters, but if you dont just move the decimal 3 to the right in your final answer. so when plugging these numbers in to your calculator and trying to find x, you get 11.20665 liters using significant figures the answer is 11.2 liters