What is the energy photon with a frequency of 2.22 x 10^14 1/s ?

1.47 x 10⁻¹⁹J

Explanation:

Given parameters;

Frequency of wave  = 2.22 x 10¹⁴/s

Unknown:

Energy of the photon = ?

Solution:

The energy of a photon can be mathematically derived using the expression below;

        E = hf

  E is the energy

 h is the Planck's constant = 6.63 x 10⁻³⁴m²kg/s

 f is the frequency  

Insert the parameters and solve;

 E = 6.63 x 10⁻³⁴m²kg/s x  2.22 x 10¹⁴/s  

 E = 14.7 x 10⁻²⁰J or 1.47 x 10⁻¹⁹J

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

hope this mark me brainliest

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o