Assume that only non-metals are involved in the formation of the following compound, containing: containing: - one atom belonging to an element in group 14 and - two atoms belonging to an element in group 1 and - one atom belonging to an element in group 16. What is the molecular shape of this compound according to the VSEPR model? A. linear B. trigonal pyramidal C. square planar D. trigonal planar E. tetrahedral bent

Option D.

Explanation:

The correct answer is option D that is Trigonal planar because of the data or following information given from the question;

=> "one atom belonging to an element in group 14".

This means that one atom has a lesser electronegativity. And this atom will be the central atom (reason: central atoms have less electronegativity).

=>" two atoms belonging to an element in group 1"

One of the characteristics of group one is it ability to form only one bond, here we will be considering the number of bonds which is one.

=>" one atom belonging to an element in group 16."

Here, we have two bonds.

Thus ,the molecules has one single bonds for each atoms and one double bonds for the last description. We have 3 atoms bonded at 120° each to the central atom.