Be sure to answer all parts. The equilibrium constant Kc for the reaction below is 61.5 at a certain temperature. H2(g) + I2(g) ⇆ 2HI(g) If you start with 0.155 M hydrogen iodide, what will the concentrations of H2, I2, and HI be at equilibrium?

Explanation:

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In this case, for the undergoing chemical reaction, we can write the equilibrium expression as shown below:

However, since the reactions starts with 0.155 M hydrogen iodide, we need to invert the reaction as well as the equilibrium expression:

And each concentration at equilibrium in terms of the reaction extent is:

Thus, plugging in the new expression we write:

Which has the following valid solution for :

Because the other solution is negative. Therefore, the concentration of hydrogen, iodine and hydrogen iodide at equilibrium turns out:

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it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.