Chemistry, 08.10.2019 08:30 22chandlerlashley

What is the molecular equation of sodium chloride and lead (ii) acetate

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Answer from: sherlyndaniel89

A molecular equation : Pb(CH3COO)₂(aq) + 2NaCl(aq)⇒ PbCl₂(s) + 2CH₃COONa (aq)

Further explanation

The equation of a chemical reaction can be expressed in the equation of the ions or molecular equation

For strong electrolytes (the ionization rate = 1) is written in the form of separate ions, while the weak electrolyte (degree of ionization <1) is still written as an un-ionized molecule

In the ion equation, there is an ion spectator that is the ion which does not react because it is present before and after the reaction

When these ions are removed, the ionic equation is called the net ionic equation

For gases and solids including water (H₂O) can be written as molecule

A molecular equation is a chemical equation expressed as a molecule

Double-Replacement reactions occur if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

To predict whether this reaction can occur or not is one of them, the precipitation reaction. A precipitation reaction occurs if two ionic compounds which are dissolved reacted to produce one of the products of the ion compound does not dissolve. Formation of these precipitating compounds that cause reactions can occur

Solubility Rules:

soluble compound

All compounds of Li⁺, Na⁺, K⁺, Rb⁺, Cs⁺, and NH₄⁺ All compounds of NO₃⁻ and C₂H₃O₂⁻ Compounds of Cl⁻, Br⁻, I⁻ except Ag⁺, Hg₂²⁺, Pb²⁺ Compounds of SO₄²⁻ except Hg₂²⁺, Pb²⁺, Sr²⁺, Ba²⁺

The reaction between sodium chloride and lead (II) acetate can occur due to the formation of precipitated compounds namely PbCl₂

A molecular equation

Pb (CH₃COO)₂(aq) + 2NaCl⁻(aq)> PbCl₂(s)+ 2CH₃COONa(aq)

Learn more

the net ionic equation

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Answer from: Quest

electron microscopy and scanning tunneling microscopes gives us a greater understanding of atoms by being able to see the atom itself, and lets us see some atomic reactions.

explanation:

Answer from: Quest

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