If you mass 0.430 g of Co(NO3)2 6H2O and dissolve it in water, what further information would you need to calculate:. a. the number of moles of Co(NO3)2 in the solution?
b. the molarity of the solution

a. No information is required.

b. The volume of the solution.

Explanation:

Hello!

In this case, since hydrates are salts which have additional water in their structures, when making mole-mass calculations involving them, we need to consider the how many water molecules we find in the hydrate. In such a way, for 0.430 g of cobalt nitrate hexahydrate (six water molecules), we proceed as follows:

a. Since we have 0.430 g of hydrate, we may compute the moles of anhydrous cobalt nitrate by using the molar mass of the hydrate (291.04 g/mol) and then, by noticing that one mole hydrate has one mole of anhydrous, we are able to compute the moles of anhydrous cobalt nitrate as shown below:

It means no further information is required.

b. Since the molarity is defined by the division of the moles of solute over liters of solution (M=mol/V), we would need the volume of the solution to successfully compute it.

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most likely he is cheating on you

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.