What mass of sucrose, C12H22O11, should you dissolve in 100.0 g of water to obtain a solution in which the mole fraction of C12H22O11 is 0.124?

the sucrose mass is 264.g

Explanation:

The computation of the sucrose mass is shown below;

The Molar mass of is  342.3 g/mol

And, the molar mass of is 18g/mol

The mass of be Y

Now

The moles of is

= Mass of ÷  molar mass of

= Y ÷ 342.3 mol

And,

The moles of is

= Mass of ÷  molar mass of

= 100.0 ÷ 18

= 5.56mol

Now

The molar fraction of is

= Moles of ÷  (moles of + moles of )  = 0.124

= (Y ÷ 342.3) ÷ [(Y ÷ 342.3) + 5.56] = 0.124

Y ÷ 342.3 = 0.124 × [(Y ÷ 342.3 + 5.56]

Y = 0.124 × Y + (0.124 × 5.56 × 342.3)

Y = 269.4 g

hence, the sucrose mass is 264.g

ch3 [ch2]14cooh

explanation:

false

because it does not have the potential to be entirely used up