How many moles of oxygen are needed to burn 2.7 moles of methyl alcohol (CH3OH)?
2CH2OH + 302 -→ 2CO2 + 4H2O
please show how you got it

3.38 moles of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

4CH2OH + 5O2 → 4CO2 + 6H2O

From the balanced equation above,

4 moles of CH2OH required 5 moles of O2 for complete combustion.

Finally, we shall determine the number of mole of O2 needed to react with 2.7 moles of CH2OH. This can be obtained as follow:

From the balanced equation above,

4 moles of CH2OH required 5 moles of O2 for complete combustion.

Therefore, 2.7 moles of CH2OH will require = (2.7 × 5)/4 = 3.38 moles of O2 for complete combustion.

Thus, 3.38 moles of O2 is required.

it's all four options.