How many moles of nitrogen dioxide gas will be produced if 25.0 ml of 2M nitric acid react? Cu + HNO3 = Cu(NO3)2 + NO2 + H2O

0.025 moles of NO₂  will produced

Explanation:

Given data:

Moles of NO₂ formed = ?

Volume of HNO₃ = 25.0 mL

Molarity of HNO₃ = 2 M

Solution:

Chemical equation:

Cu + 4HNO₃   →        Cu(NO₃)₂ + 2NO₂ + 2H₂O

Number of moles of HNO₃:

Molarity = number of moles /  volume in L

2M = number of moles / 0.025 L

Number of moles = 2 M × 0.025 L

Number of moles = 0.05 mol

Now we will compare the moles of HNO₃  with NO₂  from balance chemical equation.

                                  HNO₃            :          NO₂

                                      4                :            2

                                 0.05               :         2/4×0.05 =0.025

0.025 moles of NO₂  will produced.

yes the answer is total mass in unchanged   : )