For the chemical reaction 2 HBr(aq) + Ba(OH), (aq) — 2H20(1) + BaBr, (aq) write the net ionic equation, including the phases. net ionic equation:

2hbr(aq)  +  ba(OH)2  (aq)  --.>  2  H20 (l)  +  Babr2 (aq)

ionic   equation  is    follows

2H^+(aq)   +  2Br^- (aq) +  Ba^2+(aq)  + OH^-(aq)   --->2H2O(l)   +  Ba^2+(aq)   +  2Br-(aq)

cancel  the  spectator  ions  in  equation  above,  that  is  Ba^2+  and  2Br^-  ions

the  net  ionic  equation   is  therefore=

2H^+(aq)   +  OH^-(aq)--->  2H2O (l)

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

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