Which atom has the lower K ionization energy? А. Na
B. Be

B. 801. C. 1086. N. 1402. O. 1314. F. 1681. Ne. 2081. 3. Na. 496. Mg. 738. Al. 577. Si. 786. P. 1012. S. 1000. Cl. 1251. Ar. 1520. 4. K ... The ionization energy of an atom is the amount of energy that is required to remove an electron ... Thus, helium has the largest first ionization energy, while francium has one of the lowest.

Missing: А. ‎| Must include: А.

Explanation:

h let me think about that

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.