How many atoms of fluorine are in 5.6x10^22 molecules of MgF2.

The number of atoms of Flourine found in 5.6x10^/²² molecules of MgF2 is; 1.12 x 10²³atoms of F

Number of MgF₂ atoms as given = 5.6 x 10²² molecules;

We are required to determine the number of Fluorine atoms found in the compound.

In MgF₂,

As given, MgF₂ contains 5.6 x 10²²atoms;

Hence, 5.6 x 10²²atoms of MgF₂ will contain 2 x 5.6 x 10²² = 1.12 x 10²³atoms of Flourine.

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1.12 x 10²³atoms of F

Explanation:

Number of MgF₂ atoms = 5.6 x 10²² molecules;

 The unknown here is the number of Fluorine atoms found in the compound.

In MgF₂,

     1 mole of MgF₂ contains 2 moles of F;

From the given number of molecules we can also say that, MgF₂ contains 5.6 x 10²²atoms;

           1 mole of MgF₂ contains 2 moles of F;

    5.6 x 10²²atoms of MgF₂ will contain 2 x   5.6 x 10²² = 1.12 x 10²³atoms of F

if you mean hydrogen and oxygen then water is the product

a is the correct answer